Answered questions

Author: MahirShah300

Sprint-2/3-mandatory-interpret/3-to-pounds.js

@@ -2,13 +2,13 @@ const penceString = "399p";
 
 const penceStringWithoutTrailingP = penceString.substring(
   0,
-  penceString.length - 1
+  penceString.length - 1,
 );
 
 const paddedPenceNumberString = penceStringWithoutTrailingP.padStart(3, "0");
 const pounds = paddedPenceNumberString.substring(
   0,
-  paddedPenceNumberString.length - 2
+  paddedPenceNumberString.length - 2,
 );
 
 const pence = paddedPenceNumberString
@@ -25,3 +25,29 @@ console.log(`£${pounds}.${pence}`);
 
 // To begin, we can start with
 // 1. const penceString = "399p": initialises a string variable with the value "399p"
+
+// 2. const penceStringWithoutTrailingP = penceString.substring(
+//  0,
+//  penceString.length - 1
+//);
+// finds a substring starting at 0 index to 1 before the last index, and assigns the
+// substring to penceStringWithoutTrailingP. This removes the p and leaves us with just
+// the number
+
+// 3. const paddedPenceNumberString = penceStringWithoutTrailingP.padStart(3, "0");
+// Makes it so that the string is always at least 3 characters, by adding leading 0 until
+// it is 3 characters long.
+
+// 4. const pounds = paddedPenceNumberString.substring(
+//  0,
+//  paddedPenceNumberString.length - 2,
+//);
+// Finds the substring of number paddedPenceNumberString, with the last 2 digits cut off
+// basically finds the number of pounds by cutting off the pence
+
+// 5. const pence = paddedPenceNumberString
+//  .substring(paddedPenceNumberString.length - 2)
+//  .padEnd(2, "0");
+// Takes the substring starting at the total length-2, to the end. Essentially taking the 
+// last 2 digits
+// Then adds 0 to the beginning so it is at least 2 characters long