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Create 4070. Minimum Rotations to Dial a Number I
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/**
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* @param {string} s
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* @return {number}
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*/
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var minRotations = function(s) {
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let ans = 0;
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let curr = 0;
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for (let i = 0; i < s.length; i++) {
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let next = Number(s[i]);
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let diff = Math.abs(curr - next);
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if (diff <= 5) {
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ans += diff;
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} else {
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ans += 10 - diff;
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}
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curr = next;
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}
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return ans;
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};

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