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haobinaa
DataStructure-DesignPattern
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DataStructure-DesignPattern
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src
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com
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haobin
/
offer
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DuplicateNumInArray.java
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54 lines (48 loc) · 1.51 KB
master
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DataStructure-DesignPattern
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offer
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DuplicateNumInArray.java
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package com.haobin.offer;
/**
* @author: HaoBin
* @create: 2019/9/16 8:51
* @description: 3-数组中重复数字
*
* 题目描述:
* 在一个长度为 n 的数组里的所有数字都在 0 到 n-1 的范围内。数组中某些数字是重复的,
* 但不知道有几个数字是重复的,也不知道每个数字重复几次。请找出数组中任意一个重复的数字
**/
public class DuplicateNumInArray {
/**
* 思路: 已知数组范围都在 [0, n-1]
* 将值为 i 的元素调整到第 i 个位置上进行求解
* 若第i个位置上已经有值为i的数了,可知i重复
* @param args
*/
public static void main(String[] args) {
int[] nums = {2, 3, 1, 0, 2, 5};
int[] duplicatuon = new int[1];
if (duplicate(nums, duplicatuon)) {
System.out.println(duplicatuon[0]);
}
}
/**
* 返回任意重复的一个,赋值duplication[0]
*/
public static boolean duplicate(int[] num, int[] duplication) {
if (num.length <= 0) {
return false;
}
for (int i = 0; i < num.length; i++) {
while (num[i] != i) {
if (num[i] == num[num[i]]) {
duplication[0] = num[i];
return true;
}
swap(num, i, num[i]);
}
}
return false;
}
public static void swap(int[] nums, int i, int j) {
int t = nums[i];
nums[i] = nums[j];
nums[j] = t;
}
}
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